2[(4x-2)+16]=6(x+15)

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Solution for 2[(4x-2)+16]=6(x+15) equation:


Simplifying
2[(4x + -2) + 16] = 6(x + 15)

Reorder the terms:
2[(-2 + 4x) + 16] = 6(x + 15)

Remove parenthesis around (-2 + 4x)
2[-2 + 4x + 16] = 6(x + 15)

Reorder the terms:
2[-2 + 16 + 4x] = 6(x + 15)

Combine like terms: -2 + 16 = 14
2[14 + 4x] = 6(x + 15)
[14 * 2 + 4x * 2] = 6(x + 15)
[28 + 8x] = 6(x + 15)

Reorder the terms:
28 + 8x = 6(15 + x)
28 + 8x = (15 * 6 + x * 6)
28 + 8x = (90 + 6x)

Solving
28 + 8x = 90 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
28 + 8x + -6x = 90 + 6x + -6x

Combine like terms: 8x + -6x = 2x
28 + 2x = 90 + 6x + -6x

Combine like terms: 6x + -6x = 0
28 + 2x = 90 + 0
28 + 2x = 90

Add '-28' to each side of the equation.
28 + -28 + 2x = 90 + -28

Combine like terms: 28 + -28 = 0
0 + 2x = 90 + -28
2x = 90 + -28

Combine like terms: 90 + -28 = 62
2x = 62

Divide each side by '2'.
x = 31

Simplifying
x = 31

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